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An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 m/s. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is :  (1) 23000 (2) 20000 (3) 34500 (4) 23500

Question. An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 m/s. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is :
(1) 23000

(2) 20000

(3) 34500

(4) 23500                                                                                            (NEET-2022)

 

Aditya Bhatt Answered question 12 February 2024
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