An amount of ice of mass 10^-3 kg and temperature -10°c is transformed to vapour of temperature 110° by applying heat. The total amount of work

An amount of ice of mass 10^–3 kg and temperature –10°C is transformed to vapour of temperature 110° by applying heat. The total amount of work required for this conversion is, (Take, specific heat of ice = 2100 Jkg^–1K^–1, specificheat of water = 4180 Jkg^–1K^–1, specific heat of steam = 1920 Jkg^–1K^–1, Latent heat of ice = 3.35 × 105 Jkg^–1 and Latent heat of steam = 2.25 × 106 Jkg^–1) 

(1) 3022 J 

(2) 3043 J 

(3) 3003 J 

(4) 3024 J         (JEE-2025)