A parallel plate capacitor of capacitance 12.5 pF is charged by a battery connected between its plates to potential difference

A parallel plate capacitor of capacitance 12.5 pF is charged by a battery connected between its plates to potential difference of 12.0 V. The battery is now disconnected and a dielectric slab (Er = 6) is inserted between the plates. The change in its potential energy after inserting the dielectric slab is _______× 10^–12 J.     (JEE-2024)