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Physics | CBSE | JEE | NEET
🧑🏫 Author: Aditya Bhatt Sir |
🕒 Last Updated: July 13, 2025
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Toggle📘Question
A parallel-plate capacitor of capacitance 40F is connected to a 100 V power supply. Now the intermediate space between the plates is filled with a dielectric material of dielectric constant K = 2. Due to the introduction of dielectric material, the extra charge and the change in the electrostatic energy in the capacitor, respectively, are –
(1) 2 mC and 0.2 J
(2) 8 mC and 2.0 J
(3) 4 mC and 0.2 J
(4) 2 mC and 0.4 J (JEE-2025)
✅ Answer
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