The potential energy function (in J) of a partical in a region of space is given as U = (2x² + 3y³ + 2z) Here x, y and z are in meter.The magnitude of x – component of force (in N) acting on the particle at point P (1, 2, 3) m is :

(1) 2 

(2) 6 

(3) 4 

(4) 8 

                                        JEE-2024       

Solution:                
The potential energy function (in J) of a partical in a region of space is given as U = (2x² + 3y³ + 2z) Here x, y and z are in meter.The magnitude of x - component of force (in N) acting on the particle at point P (1, 2, 3) m is : (1) 2 (2) 6 (3) 4 (4) 8 JEE-2024

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