The position of a particle moving on x-axis is given by x(t) = A sin t + B cos^t+ ct^2+D, where t is time. The dimension of

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📘Question

The position of a particle moving on x-axis is given by x(t) = A sin t + B cos2t + Ct^2 + D, where t is time. The dimension of ABC/ D is- 

(1) L

(2) L^3 T^–2 

(3) L^2 T^–2

(4) L^2                                                   (JEE-2025) 

✅ Answer

The position of a particle moving on x-axis is given by x(t) = A sin t + B cos2t + Ct^2 + D, where t is time. The dimension of ABC/ D is-  (1) L (2) L^3 T^–2  (3) L^2 T^–2 (4) L^2 

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