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An alternating emf E = 440 sin 100 πt is applied to a circuit containing an inductance of

Q. An alternating emf E = 440 sin 100 πt is applied to a circuit containing an inductance of √2/π. If an a.c. ammeter is connected in the circuit, its reading will be :

 (A) 4.4 A

(B) 1.55 A

(C) 2.2 A

(D) 3.11 A                                 (JEE-2022)

 

 

Aditya Bhatt Answered question 29 January 2024
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