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Bhautik Study

Q. A carbon resistor of (47 ± 4.7) kΩ is to be marked with rings of different colours for its identification. The colour code sequence will be
(1) Yellow – Green – Violet – Gold
(2) Yellow – Violet – Orange – Silver
(3) Violet – Yellow – Orange – Silver
(4) Green – Orange – Violet – Gold                                                                                                                                                                                                                                                                                              (NEET-2018)

(NEET-2018)
NTA Solutions (2):-

Aditya Bhatt Changed status to publish 3 May 2024
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