In an alpha particle scattering experiment distance of closest approach for the alfa particle is 4.5×10^–14 m. If target nucleus has atomic number 80, then maximum velocity of alfa-particle is_______× 10^5 m/s approximately.

                                                                          JEE-2024

Solution:                
In an alpha particle scattering experiment distance of closest approach for the  particle is 4.5×10^–14 m. If target nucleus has atomic number 80, then maximum velocity of alfa-particle is _______× 10^5 m/s approximately. JEE-2024

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