If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is ………. × 10^–2 MeV. (Given 1 u = 931 MeV/c^2, atomic mass of helium = 4.002603 u)

                                                                     JEE-2024

Solution:                
If three helium nuclei combine to form a carbon nucleus then the energy released in this reaction is .......... × 10^–2 MeV. (Given 1 u = 931 MeV/c^2, atomic mass of helium = 4.002603 u) JEE-2024

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