If the total energy transferred to a surface in time t is 6.48 × 10^5 J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :
(1) 2.46 × 10^–3 kg m/s
(2) 2.16 × 10^–3 kg m/s
(3) 1.58 × 10^–3 kg m/s
(4) 4.32 × 10^–3 kg m/s
JEE-2024
Solution:
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