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Toggle## Class 10 maths 6.3 NCERT solutions

# NCERT Solutions For Class 10 Maths Chapter 6 Triangles Ex-6.3

##### Download the free NCERT Maths Chapter 6 Solutions for Class 10 here Triangles in Maths Class 10 NCERT Solutions are a great resource for homework assistance. For class 10 maths 6.3 NCERT solutions Expert Bhautikstudy.com Teachers developed the NCERT Solutions. Complete solutions to all the problems in NCERT Textbook’s Chapter 6 Math Class 10 Triangles Exercise 6.3.

Class 10 Maths 6.3 NCERT Solutions Question 1.

1.State which pairs of triangles in the given figures are similar. Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form :

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 2.

**2. In figure 6.35, ΔODC ~ ΔOBA, ∠ BOC = 125° and ∠ CDO = 70°. Find ∠ DOC, ∠ DCO and ∠ OAB.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 3.

**3. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that AO/OC = OB/OD**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 4.

**4. In the fig.6.36, QR/QS = QT/PR and ∠1 = ∠2. Show that ΔPQS ~ ΔTQR.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 5.

**5. S and T are point on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ~ ΔRTS.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 6.

**6. In the figure, if ΔABE ≅ ΔACD, show that ΔADE ~ ΔABC.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 7.

**7. In the figure, altitudes AD and CE of ΔABC intersect each other at the point P. Show that:**

**(i) ΔAEP ~ ΔCDP(ii) ΔABD ~ ΔCBE(iii) ΔAEP ~ ΔADB(iv) ΔPDC ~ ΔBEC**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 8.

**8. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that ΔABE ~ ΔCFB.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 9.

**9. In the figure, ABC and AMP are two right triangles, right angled at B and M, respectively, prove that:**

**(i) ΔABC ~ ΔAMP**

**(ii) CA/PA = BC/MP**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 10.

**10. CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of ΔABC and ΔEFG respectively.If ΔABC ~ ΔFEG, Show that:**

**(i) CD/GH = AC/FG(ii) ΔDCB ~ ΔHGE(iii) ΔDCA ~ ΔHGF**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 11.

**11. In the following figure, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD ⊥ BC and EF ⊥ AC, prove that ΔABD ~ ΔECF.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 12.

**12. Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of ΔPQR (see Fig 6.41). Show that ΔABC ~ ΔPQR.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 13.

**13. D is a point on the side BC of a triangle ABC such that ∠ADC = ∠BAC. Show that CA ^{2} = CB.CD**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 14.

**14. Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of anothertriangle PQR. Show that ΔABC ~ ΔPQR.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 15.

**15. A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.**

**Solution:**

Class 10 Maths 6.3 NCERT Solutions Question 16.

**16. If AD and PM are medians of triangles ABC and PQR, respectively where ΔABC ~ ΔPQR prove that AB/PQ = AD/PM.**

**Solution:**

## Maths in Class 10: Triangles

###### In Class 10 Maths 6.3 NCERT Solutions Students will talk about patterns in terms that come after those that come after by adding a certain number to the terms that came before in this chapter. Additionally, they see how to calculate the sum of n successive terms and the nth term. When students tackle real-world situations, they will successfully understand Triangles.

#### Basic Proportionality Theorem (BPT) and its Converse

Basic Proportionality Theorem

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then other two sides are divided in the same ratio. Thus in ∆ABC, if DE || BC, then

Converse of BPT

If a line divides any two sides of a triangle in the same ratio, then the line is parallel to the third side,

##### Every step of the solutions offered by Bhautik Study is discussed in great depth and with clarity. To help students better prepare for their board exams, subject matter experts have created the NCERT Class 10 Maths Solutions. These answers will be useful not only for studying for exams but also for completing assignments and homework.

The NCERT textbooks are frequently the source of questions on the CBSE Class 10 test, either directly or indirectly. Therefore, one of the greatest tools for getting ready and equipping oneself to tackle any kind of exam question from the chapter is the NCERT Solutions for Class 10 Maths Chapter 6 Triangles.

## What is the Advantage of Class 10 Maths NCERT Solutions Chapter 6 Provided by Bhautik Study?

Class 10 Maths 6.3 NCERT Solutions

In mathematics, a triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. In class 10, students typically learn about various properties and concepts related to triangles. Here’s a brief overview of what is usually covered in Class 10 Maths 6.3 NCERT Solutions:

Types of Triangles:

- Equilateral Triangle: All three sides are of equal length, and all three angles are equal (each measuring 60 degrees).
- Isosceles Triangle: Two sides are of equal length, and consequently, two angles are equal.
- Scalene Triangle: No sides are of equal length, and no angles are equal.

Angles:

- Sum of Angles: The sum of the interior angles of a triangle is always 180 degrees.
- Exterior Angle: The exterior angle of a triangle is equal to the sum of the two opposite interior angles.

Properties:

- Side Lengths: The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem).
- Altitudes: Perpendiculars drawn from each vertex to the opposite side are called altitudes. The point where the altitude intersects the side is called the foot of the altitude.
- Medians: A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side.
- Angle Bisectors: An angle bisector of a triangle is a line segment that bisects one of the vertex angles of the triangle.
- Orthocenter: The point where all three altitudes of a triangle intersect.
- Centroid: The point where all three medians of a triangle intersect.
- Circumcenter: The point where the perpendicular bisectors of the sides of a triangle intersect.

Congruence and Similarity:

- Triangles are congruent if their corresponding sides and angles are equal.
- Triangles are similar if their corresponding angles are equal and their corresponding sides are in proportion.

Pythagoras Theorem:

- In a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Area of a Triangle:

- Various methods can be used to calculate the area of a triangle, including the formula: Area = (1/2) * base * height.

These are some fundamental concepts related to triangles that are typically covered in class 10 mathematics curriculum. Students often solve problems and apply these concepts to various geometric and real-world situations here Class 10 Maths 6.3 NCERT Solutions play an important role.