A particle is moving in one dimension (along x axis) under the action of a variable force. It’s initial position was 16 m right of origin. The variation of its position (x) with time (t) is given as x = –3t³ + 18t² + 16t, where x is in m and t is in s. The velocity of the partical when its acceleration became zero is _____________m/s.
JEE-2024
Solution:
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