A force F = + x^2acts on an object in the x-direction. The work done by the force is 5J when Bhautik Study Physics | CBSE | JEE | NEET 🧑🏫 Author: Aditya Bhatt Sir | 🕒 Last Updated: July 13, 2025 Table of Contents Toggle 📘Question✅ Answer 📘Question A force F = α+βx^2 acts on an object in thex-direction. The work done by the force is 5J when the object is displaced by 1 m. If the constant α = 1N then β will be (1) 15 N/m^ (2) 10 N/m^2 (3) 12 N/m^2 (4) 8 N/m^2 (JEE-2025) ✅ Answer Ans. (3) 🚀 Learn more at BhautikStudy.com 📘 This content is provided by Bhautik Study — for CBSE, JEE, and NEET physics preparation. Visit: www.bhautikstudy.com