At the interface between two materials having refractive indices n1 and n2 the critical angle for reflection of an em wave is

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📘Question

At the interface between two materials having refractive indices n1 and n2 , the critical angle for reflection of an em wave is 1C. The n2            material is replaced by another material having refractive index n3   , such that the critical angle at the interface between n1 and n3 materials is 2C. If n3 n2 > n1;

                                                                (JEE-2025)

✅ Answer

At the interface between two materials having refractive indices n1 and n2 , the critical angle for reflection of an em wave is 1C. The n2 material is replaced by another material having refractive index n3 , such that the critical angle at the interface between n1 and n3 materials is 2C. If n3 > n2 > n1 ; 2 3 n 2 n 5  and 2C 1C 1 sin sin 2     , then 1C is

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